Optimal. Leaf size=191 \[ -\frac{\sqrt [4]{3 x^2-1}}{4 x^2}+\frac{15 \log \left (\sqrt{3 x^2-1}-\sqrt{2} \sqrt [4]{3 x^2-1}+1\right )}{16 \sqrt{2}}-\frac{15 \log \left (\sqrt{3 x^2-1}+\sqrt{2} \sqrt [4]{3 x^2-1}+1\right )}{16 \sqrt{2}}-\frac{3}{4} \tan ^{-1}\left (\sqrt [4]{3 x^2-1}\right )+\frac{15 \tan ^{-1}\left (1-\sqrt{2} \sqrt [4]{3 x^2-1}\right )}{8 \sqrt{2}}-\frac{15 \tan ^{-1}\left (\sqrt{2} \sqrt [4]{3 x^2-1}+1\right )}{8 \sqrt{2}}-\frac{3}{4} \tanh ^{-1}\left (\sqrt [4]{3 x^2-1}\right ) \]
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Rubi [A] time = 0.399893, antiderivative size = 191, normalized size of antiderivative = 1., number of steps used = 17, number of rules used = 13, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.542 \[ -\frac{\sqrt [4]{3 x^2-1}}{4 x^2}+\frac{15 \log \left (\sqrt{3 x^2-1}-\sqrt{2} \sqrt [4]{3 x^2-1}+1\right )}{16 \sqrt{2}}-\frac{15 \log \left (\sqrt{3 x^2-1}+\sqrt{2} \sqrt [4]{3 x^2-1}+1\right )}{16 \sqrt{2}}-\frac{3}{4} \tan ^{-1}\left (\sqrt [4]{3 x^2-1}\right )+\frac{15 \tan ^{-1}\left (1-\sqrt{2} \sqrt [4]{3 x^2-1}\right )}{8 \sqrt{2}}-\frac{15 \tan ^{-1}\left (\sqrt{2} \sqrt [4]{3 x^2-1}+1\right )}{8 \sqrt{2}}-\frac{3}{4} \tanh ^{-1}\left (\sqrt [4]{3 x^2-1}\right ) \]
Antiderivative was successfully verified.
[In] Int[1/(x^3*(-2 + 3*x^2)*(-1 + 3*x^2)^(3/4)),x]
[Out]
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Rubi in Sympy [A] time = 35.0296, size = 173, normalized size = 0.91 \[ \frac{15 \sqrt{2} \log{\left (- \sqrt{2} \sqrt [4]{3 x^{2} - 1} + \sqrt{3 x^{2} - 1} + 1 \right )}}{32} - \frac{15 \sqrt{2} \log{\left (\sqrt{2} \sqrt [4]{3 x^{2} - 1} + \sqrt{3 x^{2} - 1} + 1 \right )}}{32} - \frac{3 \operatorname{atan}{\left (\sqrt [4]{3 x^{2} - 1} \right )}}{4} - \frac{15 \sqrt{2} \operatorname{atan}{\left (\sqrt{2} \sqrt [4]{3 x^{2} - 1} - 1 \right )}}{16} - \frac{15 \sqrt{2} \operatorname{atan}{\left (\sqrt{2} \sqrt [4]{3 x^{2} - 1} + 1 \right )}}{16} - \frac{3 \operatorname{atanh}{\left (\sqrt [4]{3 x^{2} - 1} \right )}}{4} - \frac{\sqrt [4]{3 x^{2} - 1}}{4 x^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(1/x**3/(3*x**2-2)/(3*x**2-1)**(3/4),x)
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Mathematica [C] time = 0.303299, size = 136, normalized size = 0.71 \[ -\frac{90 F_1\left (\frac{11}{4};\frac{3}{4},1;\frac{15}{4};\frac{1}{3 x^2},\frac{2}{3 x^2}\right )}{11 \left (3 x^2-2\right ) \left (3 x^2-1\right )^{3/4} \left (45 x^2 F_1\left (\frac{11}{4};\frac{3}{4},1;\frac{15}{4};\frac{1}{3 x^2},\frac{2}{3 x^2}\right )+8 F_1\left (\frac{15}{4};\frac{3}{4},2;\frac{19}{4};\frac{1}{3 x^2},\frac{2}{3 x^2}\right )+3 F_1\left (\frac{15}{4};\frac{7}{4},1;\frac{19}{4};\frac{1}{3 x^2},\frac{2}{3 x^2}\right )\right )} \]
Warning: Unable to verify antiderivative.
[In] Integrate[1/(x^3*(-2 + 3*x^2)*(-1 + 3*x^2)^(3/4)),x]
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Maple [F] time = 0.14, size = 0, normalized size = 0. \[ \int{\frac{1}{{x}^{3} \left ( 3\,{x}^{2}-2 \right ) } \left ( 3\,{x}^{2}-1 \right ) ^{-{\frac{3}{4}}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(1/x^3/(3*x^2-2)/(3*x^2-1)^(3/4),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{{\left (3 \, x^{2} - 1\right )}^{\frac{3}{4}}{\left (3 \, x^{2} - 2\right )} x^{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((3*x^2 - 1)^(3/4)*(3*x^2 - 2)*x^3),x, algorithm="maxima")
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Fricas [A] time = 0.241737, size = 335, normalized size = 1.75 \[ \frac{60 \, \sqrt{2} x^{2} \arctan \left (\frac{1}{\sqrt{2}{\left (3 \, x^{2} - 1\right )}^{\frac{1}{4}} + \sqrt{2 \, \sqrt{2}{\left (3 \, x^{2} - 1\right )}^{\frac{1}{4}} + 2 \, \sqrt{3 \, x^{2} - 1} + 2} + 1}\right ) + 60 \, \sqrt{2} x^{2} \arctan \left (\frac{1}{\sqrt{2}{\left (3 \, x^{2} - 1\right )}^{\frac{1}{4}} + \sqrt{-2 \, \sqrt{2}{\left (3 \, x^{2} - 1\right )}^{\frac{1}{4}} + 2 \, \sqrt{3 \, x^{2} - 1} + 2} - 1}\right ) - 15 \, \sqrt{2} x^{2} \log \left (2 \, \sqrt{2}{\left (3 \, x^{2} - 1\right )}^{\frac{1}{4}} + 2 \, \sqrt{3 \, x^{2} - 1} + 2\right ) + 15 \, \sqrt{2} x^{2} \log \left (-2 \, \sqrt{2}{\left (3 \, x^{2} - 1\right )}^{\frac{1}{4}} + 2 \, \sqrt{3 \, x^{2} - 1} + 2\right ) - 24 \, x^{2} \arctan \left ({\left (3 \, x^{2} - 1\right )}^{\frac{1}{4}}\right ) - 12 \, x^{2} \log \left ({\left (3 \, x^{2} - 1\right )}^{\frac{1}{4}} + 1\right ) + 12 \, x^{2} \log \left ({\left (3 \, x^{2} - 1\right )}^{\frac{1}{4}} - 1\right ) - 8 \,{\left (3 \, x^{2} - 1\right )}^{\frac{1}{4}}}{32 \, x^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((3*x^2 - 1)^(3/4)*(3*x^2 - 2)*x^3),x, algorithm="fricas")
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{x^{3} \left (3 x^{2} - 2\right ) \left (3 x^{2} - 1\right )^{\frac{3}{4}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/x**3/(3*x**2-2)/(3*x**2-1)**(3/4),x)
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GIAC/XCAS [A] time = 0.241478, size = 228, normalized size = 1.19 \[ -\frac{15}{16} \, \sqrt{2} \arctan \left (\frac{1}{2} \, \sqrt{2}{\left (\sqrt{2} + 2 \,{\left (3 \, x^{2} - 1\right )}^{\frac{1}{4}}\right )}\right ) - \frac{15}{16} \, \sqrt{2} \arctan \left (-\frac{1}{2} \, \sqrt{2}{\left (\sqrt{2} - 2 \,{\left (3 \, x^{2} - 1\right )}^{\frac{1}{4}}\right )}\right ) - \frac{15}{32} \, \sqrt{2}{\rm ln}\left (\sqrt{2}{\left (3 \, x^{2} - 1\right )}^{\frac{1}{4}} + \sqrt{3 \, x^{2} - 1} + 1\right ) + \frac{15}{32} \, \sqrt{2}{\rm ln}\left (-\sqrt{2}{\left (3 \, x^{2} - 1\right )}^{\frac{1}{4}} + \sqrt{3 \, x^{2} - 1} + 1\right ) - \frac{{\left (3 \, x^{2} - 1\right )}^{\frac{1}{4}}}{4 \, x^{2}} - \frac{3}{4} \, \arctan \left ({\left (3 \, x^{2} - 1\right )}^{\frac{1}{4}}\right ) - \frac{3}{8} \,{\rm ln}\left ({\left (3 \, x^{2} - 1\right )}^{\frac{1}{4}} + 1\right ) + \frac{3}{8} \,{\rm ln}\left ({\left |{\left (3 \, x^{2} - 1\right )}^{\frac{1}{4}} - 1 \right |}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((3*x^2 - 1)^(3/4)*(3*x^2 - 2)*x^3),x, algorithm="giac")
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